Another example Using the \( (1/2)^4 \) single-particle space, resulting in eight single-particle states
| Index | \( n \) | \( l \) | \( s \) | \( m_s \) |
| 1 | 0 | 0 | 1/2 | -1/2 |
| 2 | 0 | 0 | 1/2 | 1/2 |
| 3 | 1 | 0 | 1/2 | -1/2 |
| 4 | 1 | 0 | 1/2 | 1/2 |
| 5 | 2 | 0 | 1/2 | -1/2 |
| 6 | 2 | 0 | 1/2 | 1/2 |
| 7 | 3 | 0 | 1/2 | -1/2 |
| 8 | 3 | 0 | 1/2 | 1/2 |
and then taking only 4-particle, \( M=0 \) states that have no `broken pairs', there are six basis Slater determinants: