43.5. Solutions

Here are answers and solutions to selected exercises.

Solution to Exercise 43.1

We have the following design matrix

\[\begin{split} \dmat = \left[ \begin{array}{cc} 1 & -2 \\ 1 & 1 \end{array} \right], \end{split}\]

which in the present case yields the parameter values

\[ \pars^{*} = \dmat^{-1}\data = [1,2]^T. \]

Solution to Exercise 43.3

For the warmup case we have fitted a straight line through two data points, which is always possible, and we cannot determine the sample variance. This will be even more clear when we come to Bayesian Linear Regression.